-32x^2+32x+10=0

Solution for -32x^2+32x+10=0 equation:

-32x^2+32x+10=0

a = -32; b = 32; c = +10;
Δ = b2-4ac
Δ = 322-4·(-32)·10
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-48}{2*-32}=\frac{-80}{-64}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+48}{2*-32}=\frac{16}{-64}
=-1/4
$